Optimal. Leaf size=164 \[ \frac{3 i \text{PolyLog}\left (2,-i e^{\text{sech}^{-1}(a x)}\right )}{20 a^5}-\frac{3 i \text{PolyLog}\left (2,i e^{\text{sech}^{-1}(a x)}\right )}{20 a^5}-\frac{x^3}{30 a^2}-\frac{x^3 \sqrt{\frac{1-a x}{a x+1}} (a x+1) \text{sech}^{-1}(a x)}{10 a^2}-\frac{3 x}{20 a^4}-\frac{3 x \sqrt{\frac{1-a x}{a x+1}} (a x+1) \text{sech}^{-1}(a x)}{20 a^4}-\frac{3 \text{sech}^{-1}(a x) \tan ^{-1}\left (e^{\text{sech}^{-1}(a x)}\right )}{10 a^5}+\frac{1}{5} x^5 \text{sech}^{-1}(a x)^2 \]
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Rubi [A] time = 0.123648, antiderivative size = 164, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 6, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.6, Rules used = {6285, 5418, 4185, 4180, 2279, 2391} \[ \frac{3 i \text{PolyLog}\left (2,-i e^{\text{sech}^{-1}(a x)}\right )}{20 a^5}-\frac{3 i \text{PolyLog}\left (2,i e^{\text{sech}^{-1}(a x)}\right )}{20 a^5}-\frac{x^3}{30 a^2}-\frac{x^3 \sqrt{\frac{1-a x}{a x+1}} (a x+1) \text{sech}^{-1}(a x)}{10 a^2}-\frac{3 x}{20 a^4}-\frac{3 x \sqrt{\frac{1-a x}{a x+1}} (a x+1) \text{sech}^{-1}(a x)}{20 a^4}-\frac{3 \text{sech}^{-1}(a x) \tan ^{-1}\left (e^{\text{sech}^{-1}(a x)}\right )}{10 a^5}+\frac{1}{5} x^5 \text{sech}^{-1}(a x)^2 \]
Antiderivative was successfully verified.
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Rule 6285
Rule 5418
Rule 4185
Rule 4180
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int x^4 \text{sech}^{-1}(a x)^2 \, dx &=-\frac{\operatorname{Subst}\left (\int x^2 \text{sech}^5(x) \tanh (x) \, dx,x,\text{sech}^{-1}(a x)\right )}{a^5}\\ &=\frac{1}{5} x^5 \text{sech}^{-1}(a x)^2-\frac{2 \operatorname{Subst}\left (\int x \text{sech}^5(x) \, dx,x,\text{sech}^{-1}(a x)\right )}{5 a^5}\\ &=-\frac{x^3}{30 a^2}-\frac{x^3 \sqrt{\frac{1-a x}{1+a x}} (1+a x) \text{sech}^{-1}(a x)}{10 a^2}+\frac{1}{5} x^5 \text{sech}^{-1}(a x)^2-\frac{3 \operatorname{Subst}\left (\int x \text{sech}^3(x) \, dx,x,\text{sech}^{-1}(a x)\right )}{10 a^5}\\ &=-\frac{3 x}{20 a^4}-\frac{x^3}{30 a^2}-\frac{3 x \sqrt{\frac{1-a x}{1+a x}} (1+a x) \text{sech}^{-1}(a x)}{20 a^4}-\frac{x^3 \sqrt{\frac{1-a x}{1+a x}} (1+a x) \text{sech}^{-1}(a x)}{10 a^2}+\frac{1}{5} x^5 \text{sech}^{-1}(a x)^2-\frac{3 \operatorname{Subst}\left (\int x \text{sech}(x) \, dx,x,\text{sech}^{-1}(a x)\right )}{20 a^5}\\ &=-\frac{3 x}{20 a^4}-\frac{x^3}{30 a^2}-\frac{3 x \sqrt{\frac{1-a x}{1+a x}} (1+a x) \text{sech}^{-1}(a x)}{20 a^4}-\frac{x^3 \sqrt{\frac{1-a x}{1+a x}} (1+a x) \text{sech}^{-1}(a x)}{10 a^2}+\frac{1}{5} x^5 \text{sech}^{-1}(a x)^2-\frac{3 \text{sech}^{-1}(a x) \tan ^{-1}\left (e^{\text{sech}^{-1}(a x)}\right )}{10 a^5}+\frac{(3 i) \operatorname{Subst}\left (\int \log \left (1-i e^x\right ) \, dx,x,\text{sech}^{-1}(a x)\right )}{20 a^5}-\frac{(3 i) \operatorname{Subst}\left (\int \log \left (1+i e^x\right ) \, dx,x,\text{sech}^{-1}(a x)\right )}{20 a^5}\\ &=-\frac{3 x}{20 a^4}-\frac{x^3}{30 a^2}-\frac{3 x \sqrt{\frac{1-a x}{1+a x}} (1+a x) \text{sech}^{-1}(a x)}{20 a^4}-\frac{x^3 \sqrt{\frac{1-a x}{1+a x}} (1+a x) \text{sech}^{-1}(a x)}{10 a^2}+\frac{1}{5} x^5 \text{sech}^{-1}(a x)^2-\frac{3 \text{sech}^{-1}(a x) \tan ^{-1}\left (e^{\text{sech}^{-1}(a x)}\right )}{10 a^5}+\frac{(3 i) \operatorname{Subst}\left (\int \frac{\log (1-i x)}{x} \, dx,x,e^{\text{sech}^{-1}(a x)}\right )}{20 a^5}-\frac{(3 i) \operatorname{Subst}\left (\int \frac{\log (1+i x)}{x} \, dx,x,e^{\text{sech}^{-1}(a x)}\right )}{20 a^5}\\ &=-\frac{3 x}{20 a^4}-\frac{x^3}{30 a^2}-\frac{3 x \sqrt{\frac{1-a x}{1+a x}} (1+a x) \text{sech}^{-1}(a x)}{20 a^4}-\frac{x^3 \sqrt{\frac{1-a x}{1+a x}} (1+a x) \text{sech}^{-1}(a x)}{10 a^2}+\frac{1}{5} x^5 \text{sech}^{-1}(a x)^2-\frac{3 \text{sech}^{-1}(a x) \tan ^{-1}\left (e^{\text{sech}^{-1}(a x)}\right )}{10 a^5}+\frac{3 i \text{Li}_2\left (-i e^{\text{sech}^{-1}(a x)}\right )}{20 a^5}-\frac{3 i \text{Li}_2\left (i e^{\text{sech}^{-1}(a x)}\right )}{20 a^5}\\ \end{align*}
Mathematica [A] time = 0.362456, size = 182, normalized size = 1.11 \[ \frac{9 i \text{PolyLog}\left (2,-i e^{-\text{sech}^{-1}(a x)}\right )-9 i \text{PolyLog}\left (2,i e^{-\text{sech}^{-1}(a x)}\right )-2 a^3 x^3+12 a^5 x^5 \text{sech}^{-1}(a x)^2-6 a^3 x^3 \sqrt{\frac{1-a x}{a x+1}} (a x+1) \text{sech}^{-1}(a x)-9 a x-9 a x \sqrt{\frac{1-a x}{a x+1}} (a x+1) \text{sech}^{-1}(a x)+9 i \text{sech}^{-1}(a x) \log \left (1-i e^{-\text{sech}^{-1}(a x)}\right )-9 i \text{sech}^{-1}(a x) \log \left (1+i e^{-\text{sech}^{-1}(a x)}\right )}{60 a^5} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.404, size = 289, normalized size = 1.8 \begin{align*}{\frac{{x}^{5} \left ({\rm arcsech} \left (ax\right ) \right ) ^{2}}{5}}-{\frac{{\rm arcsech} \left (ax\right ){x}^{4}}{10\,a}\sqrt{-{\frac{ax-1}{ax}}}\sqrt{{\frac{ax+1}{ax}}}}-{\frac{3\,{\rm arcsech} \left (ax\right ){x}^{2}}{20\,{a}^{3}}\sqrt{-{\frac{ax-1}{ax}}}\sqrt{{\frac{ax+1}{ax}}}}-{\frac{{x}^{3}}{30\,{a}^{2}}}-{\frac{3\,x}{20\,{a}^{4}}}+{\frac{{\frac{3\,i}{20}}{\rm arcsech} \left (ax\right )}{{a}^{5}}\ln \left ( 1+i \left ({\frac{1}{ax}}+\sqrt{{\frac{1}{ax}}-1}\sqrt{1+{\frac{1}{ax}}} \right ) \right ) }-{\frac{{\frac{3\,i}{20}}{\rm arcsech} \left (ax\right )}{{a}^{5}}\ln \left ( 1-i \left ({\frac{1}{ax}}+\sqrt{{\frac{1}{ax}}-1}\sqrt{1+{\frac{1}{ax}}} \right ) \right ) }+{\frac{{\frac{3\,i}{20}}}{{a}^{5}}{\it dilog} \left ( 1+i \left ({\frac{1}{ax}}+\sqrt{{\frac{1}{ax}}-1}\sqrt{1+{\frac{1}{ax}}} \right ) \right ) }-{\frac{{\frac{3\,i}{20}}}{{a}^{5}}{\it dilog} \left ( 1-i \left ({\frac{1}{ax}}+\sqrt{{\frac{1}{ax}}-1}\sqrt{1+{\frac{1}{ax}}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (x^{4} \operatorname{arsech}\left (a x\right )^{2}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{4} \operatorname{asech}^{2}{\left (a x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{4} \operatorname{arsech}\left (a x\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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